\(\left[5^3.\left(3x+2\right)\right]:13=5^5:\left(13^5:13^4\right)\)

\(\left[5^3\left(3x+2\right)\right]:13=5^5:13\)

\(\left[5^3\left(3x+2\right)\right]:13=\frac{3125}{13}\)

\(\left[5^3\left(3x+2\right)\right]=3125\)

\(3x+2=3125:5^3\)

\(3x+2=25\)

\(3x=25-2\)

\(3x=23\)

\(x=\frac{23}{3}\)

\(5^3.\left(3x+2\right):13=5^5:\left(13^5:13^4\right)\)

\(5^3.\left(3x+2\right):13=3125:13\)

\(5^3.\left(3x+2\right):13=\frac{3125}{13}\)

125 . ( 3x + 2 ) : 13 =\(\frac{3125}{13}\)

125 . ( 3x + 2 ) =\(\frac{3125}{13}.\frac{13}{1}=3125\)

3x + 2              = 3125 : 125

3x + 2              = 25

3x                    = 25 -2

3x                    = 23

x                    =  23 : 3 

x                    = \(\frac{23}{3}\)

bài này tui làm cho cậu cậu tick rồi mà

\(5^3\left(3x+2\right)\div13=10^3\div\left(13^5\div13^4\right)\)

\(\Rightarrow125\left(3x+2\right)\div13=1000\div13\)

\(\Rightarrow125\left(3x+2\right)=1000\)

\(\Rightarrow3x+2=1000\div125\)

\(\Rightarrow3x+2=8\)

\(\Rightarrow3x=8-2\)

\(\Rightarrow3x=6\Rightarrow x=6\div3\Rightarrow x=2\)

Vậy : x = 2

\(\left[5^3\left(3x+2\right)\right]:13=5^5:\left(13^5:13^4\right)\)

\(\left[5^3\left(3x+2\right)\right]:13=5^5:13\)

\(5^3\left(3x+2\right)=5^5:13.13\)

\(5^3\left(3x+2\right)=5^5\)

\(3x+2=5^5:5^3\)

\(3x+2=25\)

\(3x=25-2\)

\(3x=23\)

\(\Rightarrow x=\frac{23}{3}\)

 ( 375x+250 ) :13=3125;13

375x+250=3125

375x=2875

x=23/3

\(a,\frac{7}{3}x+5=\frac{9}{6}x-7\)

\(\frac{7}{3}x-\frac{9}{6}x=-7-5\)

  \(\left(\frac{7}{3}-\frac{9}{6}\right).x=-12\)

                  \(\frac{5}{6}.x=-12\)

                        \(x=\left(-12\right):\frac{5}{6}\)

                        \(x=-\frac{72}{5}\)

\(b,3x+\frac{6}{4}=5-\frac{7x}{6}\)

\(3x+\frac{7x}{6}=5-\frac{6}{4}\)

\(\left(3+\frac{7}{6}\right).x=\frac{7}{2}\)

\(\frac{25}{6}.x=\frac{7}{2}\)

\(x=\frac{7}{2}:\frac{25}{6}\)

\(x=\frac{21}{25}\)

\(c,\frac{12}{5}x+6=\frac{17}{3}x+12\)

\(\frac{12}{5}x-\frac{17}{3}x=12-6\)

            \(-\frac{49}{15}x=6\)

                       \(x=6:\left(-\frac{49}{15}\right)\)

                       \(x=-\frac{90}{49}\)

\(d,6\left(3x+7\right)=12\left(2x-4\right)\)

       \(18x+42=24x-48\)

     \(18x-24x=-48-42\)

                 \(-6x=-90\)

                        \(x=15\)

\(e,13\left(2x-9\right)=8\left(3x-13\right)\)

      \(26x-117=24x-104\)

      \(26x-24x=-104+117\)

                      \(2x=13\)

                        \(x=\frac{13}{2}\)

3x - 2x = 13 - 19

   x      = -6

Vậy x = -6

3x + 7   = 4 - 3x

3x + 3x = 7 - 4

 6x        = 3

   x        = 3 : 6

   x        = \(\frac{1}{2}\)

Vậy x = \(\frac{1}{2}\)

5 ( x + 1 ) -3 x   = x + 9         

5 . x + 5 . 1 - 3x = x + 9

5x + 5 - 3x         = x + 9

5x - x - 3x + 5    = 9

4x - 3x               = 9 - 5

 x                      = 4

Vậy x = 4

A) 3x-2x=13-19

=>.      x=-6

   Vậy x=-6

b)3x+7=4-3x

=>3x+3x=4-7

=>.     6x=-3

=>.       x=-3/6

     Vậy x=-3/6

c)5(x+1)-3x=x+9

=>5x+5-3x=x+9

=>. 5x-3x-x=9-5

 =>.          x=4

     Vậy x=4

    Chúc bạn học tốt nhé!

    \(3x-2x=13-19\)

\(\Leftrightarrow\)\(x=-6\)

Vậy....

   \(3x+7=4-3x\)

\(\Leftrightarrow\)\(6x=-3\)

\(\Leftrightarrow\)\(x=-\frac{1}{2}\)

Vậy...

      \(5\left(x+1\right)-3x=x+9\)

\(\Leftrightarrow\)\(5x+5-3x=x+9\)

\(\Leftrightarrow\)\(x=4\)

Vậy...

\(5^3.\left(3x+2\right):13=10^3:\left(13^5:13^4\right)\)

\(125.\left(3x+2\right):13=1000:13\)

\(125.\left(3x+2\right)=1000\)

\(3x+2=1000:125\)

\(3x+2=8\)

         \(3x=6\)

            \(x=2\)

Hok tốt nha^^

=>5³.(3x+2):13=10³: 13

=>5³.(3x+2)=10³

=>(3x+2)=5³

=>3x+2=5

=>3x=3

=>x=3:3

=>x=1

\(PT\Leftrightarrow52x-108-12x-24=13\)

=>\(40x-132=13\)

=>\(40x=145\)

=>x=29/8